(2x+3)^2-4(2x+3)-12=0

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Solution for (2x+3)^2-4(2x+3)-12=0 equation: 



(2x+3)^2-4(2x+3)-12=0

We multiply parentheses

(2x+3)^2-8x-12-12=0

We add all the numbers together, and all the variables

-8x+(2x+3)^2-24=0

We move all terms containing x to the left, all other terms to the right

-8x+(2x+3)^2=24

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